Hi All, Reading through Learning Perl (3rd Ed), and messing around with Binary Assignment Operators (2.5.3).
Code is as follows : #!perl -w $fred = 4; print "Fred is now : $fred \n"; $fred += 4; print "Add 4 to Fred : $fred \n"; $fred *= 2; print "Multiply by 2 : $fred \n"; $fred -= 6; print "Subtract 6 : $fred \n"; $fred /= 2; print "Divide by 2 : $fred \n"; #$fred .= 5 $fred = $fred . 5 print "$fred \n"; And I get the following error : C:\SCRIPTS\test>perl fred.pl syntax error at fred.pl line 14, near "print" Execution of fred.pl aborted due to compilation errors. What I'm trying to do is to append 5 to the value of $fred. If you comment out the last 3 lines, you get 5 as the value for $fred. Is this a valid assignment? Is it possible to paste in a number to the end of another number to make a new number? (In this case, 55). I've also tried encapsulating the value of 5 with and without '' "" and `` And I don't reckon changing Fred into Barney will work either :o) Thanks in advance, DerekB ************************************************************************ Meteor web site http://www.meteor.ie ************************************************************************ -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
