Hello
Please don't cross post
An argument passed to a subroutine returns wrong value.
Code example:
@x = (1..5); $x = @x;
You are trying to assign an array to a scalar. An array evaluated in a scalar context gives the no elements present in it. In this case the value 5 will be assigned to $x.
showValue ($x); # or showValue (\$x);
sub showValue {
my $forwarded = @_;
Assigning an array to a scalar again. In this case the array @_ is an one element array containing the value 5 or the reference to $x depending on your call (perldoc perlsub).
print $forwarded; # print ${$forwarded};
If the strict pragma had been enabled (use strict), print ${$forwarded} will result in a fatal error.
}
In both cases, the script prints out 1. What is going on here?
Thanks
Babs
-- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
