"R. Joseph Newton" wrote: > > "John W. Krahn" wrote: > > > > Try it like this: > > > > perl -le 'print eval "@ARGV"' > > Good on 'nix/'nux, I guess. On Windows, It takes a little different quoting:
You mean like: perl -le "print eval [EMAIL PROTECTED]" > Greetings! E:\d_drive\perlStuff>perl -le "print eval $ARGV[0]" "2 + 3" > 5 No, I guess you didn't. > What happens is simply that the eval @ARGV statement calls the count of elements, Are you implying that an array in a double quoted string is in scalar context? (To the beginners out there, an array in a double quoted string expands to all the elements of the array separated by the contents of the $" variable.) > probably not what the OP had in mind. Hmmm, lets see how join handles the original > formulation--still needs double-quotes on Win, though > > Greetings! E:\d_drive\perlStuff>perl -le "print eval join / /, @ARGV" 2 + 3 > 5 $ perl -wle 'print eval join / /, @ARGV' 5 + 5 / / should probably be written as " " at -e line 1. Use of uninitialized value in pattern match (m//) at -e line 1. 10 Your perl statement is equivalent to: print eval join $_ =~ / /, @ARGV And it only works because "$_ =~ / /" evaluates to '' and '2+3' gives the same answer as '2 + 3'. John -- use Perl; program fulfillment -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
