Manish Uskaikar wrote:
> Hi All,
>
> I would like to "zip" a file using perl script. I used following command:-
>
> system ("zip <zip name> <file name>");
>
> However this command fails when the filename is more than 8 characters.
Not true. I just tested, and filenames were not rejected for length. It does not
ignore whitespace, though, and there doesn't seem to be any way to escape whitespace
characters.
> Since DOS does not support more than 8 characters.
Wouldn't make any difference on Win2K. It doesn't use DOS for its command
environment, although the interface does closely resemble DOS. It is a shell escaping
issue.
> Is there any way by which I can zip a file, whose name is 9+ characters long? I am
> working on Windows 2000.
Sure. Just do it. If your filename has spaces, you do have a problem. I like the
suggestion of using a module, since you are doing it from Perl. No point in shelling
out. For what its worth, the program itself doesn't have any problem even with spaces
in filenames. I just zipped a directory with long filenames inside it, and they
worked fine. Thanks for letting me know about this command-line tool.
> Regards
>
> Manish U
Joseph
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