As far as I can see... The split() function returns a list, not a scalar. When you tried to assign it to a scalar, it tried to assign the result to @_ and then assign the number of items in @_ to $type. Maybe I'm wrong, someone else will probably correct me i so. In any case, I'm almost 100% sure that isn't what you want.
-----Original Message----- From: Eric Walker [mailto:[EMAIL PROTECTED] Sent: Wednesday, January 14, 2004 3:03 PM To: perlgroup Subject: error. Does anyone know what this means... code.. for ($i = 0;$i <= $size; $i+=$temp){ $type = split(::,shift (@hold)); } Warning: Use of implicit split to @_ is deprecated at .//test.pl line 21 help, thanks perlknucklehead -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] <http://learn.perl.org/> <http://learn.perl.org/first-response>
