Michael C. Davis wrote: > > At 01:31 AM 2/28/04 +1100, David le Blanc wrote: > >Now remember, a perl 'prototype' is not a prototype in the regular > >sense, > >but a method to override perl's natural greedy argument list collection, > >and a method to create functions which emulate perl's builtins (ie, > >provide > >hints to the expected calling context). > > Good point. > > Just so I'm clear ... will the prototype still apply if someone calls the > subroutine by explicit module name e.g. > > my $x = MyProject::ModuleName::MySub; > > without importing any symbols from the module, in the case when the module > does not export any names by default? Or is importing/exporting a separate > issue from prototypes? It seems there are some hoops one has to jump > through to make sure that the prototype is 'known' for any given subroutine > call, but I'm not real clear as to just what those hoops are ...
You're now asking a question where I can just say, "Try it!". I won't know without doing a trial, and if you can both help and ask questions then you'll be highly sought-after :) Well done. Rob -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] <http://learn.perl.org/> <http://learn.perl.org/first-response>
