> This is where the work gets done, yes.  In English
> it reads, for every 
> word in the array, add one to the corresponding hash
> value under that 
> key.  That will give you a hash with keys for all
> the words.  Their 
> values will be the number of times that word
> appeared in the array.  
> That's often useful, but in this case we can safely
> discard the values 
> as the keys alone provide our answer.  Make sense?
> 

It makes perfect sense.  Thanks.

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