From: "Rob Dixon" <[EMAIL PROTECTED]> > Jenda Krynicky wrote: > > > > From: "Jayakumar Rajagopal" <[EMAIL PROTECTED]> > > > hi friends, > > > in regexp, I feel \s and \b behaves same. > > > can someone send me a contradiction ? > > > > $str = "This is a sentence. And this is another."; > > > > @all_words = ($str =~ /\b(\w+)\b/g); > > print join( ', ', @all_words), "\n"; > > > > @some_words = ($str =~ /\s(\w+)\s/g); > > print join( ', ', @some_words), "\n"; > > > > Quite a big difference ain't it? > > > > \b matches 0 characters just between a word and non-word character, > > while \s matches one space. > > Except that the second case doesn't find 'a' or 'this' because the > match for their preceding words chews up the whitespace that would > delimit them.
That was the whole point. Jayakumar though \b and \s behave the same so I gave him an example that shows that they don't. I never said the second regexp matches all words. > Something else worth pointing out: \b considers the beginning or end > of the string to be equivalent to a \W (non-word) match, so the first > case also found 'This' at the start of the string. > > Finally, if you just need to find all the 'word-character' substrings > then there's no need for either \b or \s: > > @all_words = ($str =~ /\w+/g); > print join( ', ', @all_words), "\n"; > > **OUTPUT > > This, is, a, sentence, And, this, is, another Agreed. Jenda ===== [EMAIL PROTECTED] === http://Jenda.Krynicky.cz ===== When it comes to wine, women and song, wizards are allowed to get drunk and croon as much as they like. -- Terry Pratchett in Sourcery -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] <http://learn.perl.org/> <http://learn.perl.org/first-response>
