----- Original Message ----- From: WC -Sx- Jones Sent: 21.04.2004, 14:23 Uhr
>Jan Eden wrote: > >> if (season($start_date) && season($end_date) { >> $season_days = Delta_Days($start_date, $end_date) >> } elsif season($start_date) { > > >try not to make it *more* complicated :) > >You posted your own answer in the first post. > >Consider: > >((season($start_date) && (season($end_date)) ? > go sub for $80 : or go sub for $55; > >Or however you want to test for Summer. I'm afraid it's not that simple. Consider a start date of June 13 and an end date of June 20. In that case, season($start_date) will return false, making the whole test expression false. But only the first three days will cost $55 in that case. So the calculation should be: $other_days = Delta_Days($start_day, $div_day); $season_days = Delta_Days($div_day, $end_day); And I have exactly three other situations: $season_days = Delta_Days($start_day, $end_day); --- $other_days = Delta_Days($start_day, $end_day); --- $season_days = Delta_Days($start_day, $div_day2); $other_days = Delta_Days($div_day2, $end_day); To capture the four possible configurations correctly, the condition given above is not sufficient. Thanks, Jan -- There are 10 kinds of people: those who understand binary, and those who don't -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] <http://learn.perl.org/> <http://learn.perl.org/first-response>