Other command can instance? Because after try still no work.
-----Original Message----- From: John W. Krahn [mailto:[EMAIL PROTECTED] Sent: Thursday, May 27, 2004 9:37 AM To: [EMAIL PROTECTED] Subject: Re: How to find same filename in subdirectory > Hi, John thanks you comment, the coding is work. But i'm detect have some small > problem in line 7 print "$File::Find::name\n" if $_ eq 'File1'; I test as below > sample 2 is follow you coding. From here i detect nothing return from script. > > But after i amend the coding become print "$File::Find::name\n" if $_ = 'File1'; > this work and return the result i expected. But why perl show "Found = in > conditional, should be == at ./callback line 7."? Any idea? I try put "==" to > replace "=", the result return like sample 2. Perhaps you want this instead: print "$File::Find::name\n" if /File1$/; John -- use Perl; program fulfillment -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] <http://learn.perl.org/> <http://learn.perl.org/first-response> -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] <http://learn.perl.org/> <http://learn.perl.org/first-response>
