[EMAIL PROTECTED] wrote: > Ok fantastic, I totally understand that, and if there were going to be > more than one thing passed, just insert $par2 = shift; on the next > line and then the second argument is in $par2, I assume.....right??
Yes. You might also see it this way: my ($par1, $par2) = @_; The latter construct is not destructive of @_, while using shift() is. It usually doesn't matter. -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] <http://learn.perl.org/> <http://learn.perl.org/first-response>
