So \w means the first non word character. What about the ~ / before the (\w? And what does the + sign do? Is $buf a command?
Thanks AD -----Original Message----- From: Bob Showalter [mailto:[EMAIL PROTECTED] Sent: Tuesday, October 19, 2004 8:57 AM To: 'Khairul Azmi'; [EMAIL PROTECTED] Subject: RE: simple regular expression problem Khairul Azmi wrote: > Hi all, > I am a newbie. I just need to extract the string containing the unix > account from the following text > > <[EMAIL PROTECTED]> SIZE=1024. I'm guessing you want to extract the string "user"? (But how do you know that that corresponds to a Unix account?) The following will catpure "user" from the example you gave: ($acct) = $buf =~ /(\w+)/; This works because: a) \w matches 'u', 's', 'e', and 'r', but not '<' or '@' b) regexes match the "longest, leftmost" sequence, so 'user' matches instead of 'gmail'. You would be advised to replace \w with the actual class of characters that are allowed in user names... -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] <http://learn.perl.org/> <http://learn.perl.org/first-response> -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] <http://learn.perl.org/> <http://learn.perl.org/first-response>
