In my prior emails, I have been mentioning @tail. @tail is an array and can contain a list of values. An array is the one variable that can do what you require. Please view the documentation and understand arrays and lists. A hash will work also but I believe you want an array.
perldoc perlintro perldoc perldata perldoc perllol perldoc perlreftut Happy hunting, ZO -----Original Message----- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] Sent: Saturday, October 23, 2004 12:38 PM To: [EMAIL PROTECTED] Subject: RE: How to store the out put in StringBuffer Hi Thank you very much for the mail. Say in the for loop it is printing var1 --> 1 var2 --> 2 var3 --> 3 var4 --> 4 var5 --> 5 var6 --> 6 How to store var1,2,3,4,5,6 to one variable --> $Newvar should print 1 2 3 4 5 6 A buffer kind i.e 6 lines is should store in one variable. Am I asking some thing wrong regards Sreedhar -----Original Message----- From: Zeus Odin [mailto:[EMAIL PROTECTED] Sent: 23 October 2004 17:17 To: Kalkunte-Venkatachala, Sreedhar; [EMAIL PROTECTED] Subject: RE: How to store the out put in StringBuffer If you want to print to a handle, you must print CHAT "text"; If all of your text is in @tail, you can print CHAT join '', @tail; If you still want to print $var for some reason my $var = join '', @tail; print CHAT $var; Does that make sense? Please read: perldoc -f join Perldoc -f print -ZO -----Original Message----- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] Sent: Saturday, October 23, 2004 10:53 AM To: [EMAIL PROTECTED] Subject: RE: How to store the out put in StringBuffer Hi Thank you very much for the mail. at least can you tel me how to store in one variable called $var (the result of print $_ foreach @tail;). because I can print the complete output in one shot. Regards Sreedhar -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] <http://learn.perl.org/> <http://learn.perl.org/first-response>
