I have an 11 digit number. I want to add another number to it and format to 11
digits as well.
my $amount1 = 14313562897;
my $amount2 = 00000013625;
$amount = sprintf("%011d", $amount1 + $amount2);
print $amount."\n";
The answer perl gives me is -0000000001
How can this be ?
---
When a number begins with a 0 , perl treats it as an octal value and performs
octal arithmetic
for example 020 + 0101 = (2*8 + 0*1) + ( 1*(8^2) + 0*(8^1) + 1*(8^0) ) = (16)
+ (64+1) = 81
---
As well, if the large number starts with 0, I get an "Illegal octal digit '8'
at test.pl line 2, at end of line". As though perl cant handle numbers bigger
than 10 digits or so.
????
---
If your big number starts with 0 and contains digits between 0 and 7 there
should not be any complaints by perl.
HTH,
Chetak
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