On Wed, 2005-02-02 at 09:23 -0500, Wiggins d'Anconia wrote:
> mike wrote:
> > Am I right in thinking that if you double quote the seperator in split
> > the seperator is added to the array ie:
> >
> > @array3=split(/"\t/",$value4); would add \t to the end of @array3 while
>
> As you have written it above I get a syntax error:
>
> String found where operator expected at ./test.pl line 12, at end of line
> (Missing semicolon on previous line?)
> Can't find string terminator '"' anywhere before EOF at ./test.pl line 12.
>
> If you meant, C</"\t"/> then I still don't think you will get what you
> want. C<split> just isn't that smart.
>
No the problem was that this ( with the quote in the "right" place) was
giving me what I didnt want.
this is the code
@value=param();
shift (@value);
shift (@value);
pop (@value);
print @value;
foreach $value (@value){
$value1=substr($value,0,9);
if ($value1 eq "work_emai"){
push (@value2,param($value));
push (@value2,"\t");
#print $value2;
}
else {
push (@value2,param($value));
push (@value2,'##');
#print param($value)
}
}
$value4=join('',@value2);
print br,"value4",$value4,br;
@array3=split(/\t/,$value4);
@[EMAIL PROTECTED];
with "\t" the \t was being inserted into a db field, without it
everything was hunky dory
> >
> > @array3=split(/\t/,$value4); would not
> >
>
> What are you really trying to do?
>
> http://danconia.org
>
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