I'm sorry, as I can see I have explained incorrectly a problem. In main() function I have an array (not the array reference). But function print_array() takes a reference to a part of array.
I want to give to print_array() function a reference to a part of array.
Array and that part of array may be very big and I wish to avoid excessive copying of data. Therefore I don't want use splice function.
Jay Savage wrote:
On Apr 7, 2005 8:54 AM, Vladimir D Belousov <[EMAIL PROTECTED]> wrote:
Hallo, all!
I have a function which prints array:
sub print_array { my $array_ref = shift; for(@$array_ref){ print "$_\n"; } }
And I have a big array, for example named @array. I want to print @array elements from N to N+100 using this function, but don't want to use second array (they are can be very big). After print I don't need @array anymore.
I do this: $#array = $N+100; print_array($array[$N]);
You probably don't want this. This gives leaves you with an array with $N+100 itema, but the items are $array[0] to $array[$N+100], not $array[$N] to $array[$N+100].
To print, use a slice:
foreach (@$array_ref[$n..$n+100]) { print "$_ somthing\n" ; }
If you want to resize the array, don't forget you're using array references here.
To splice (returns elements $N to $N+100): '@$arrary_ref = splice(@$arrary_ref, $N, 100)' To resize (leaves elements 0 to $N+100): '$#{$array_ref} = $N + 100'
Also, don't forget that modifying $# for an array will create undef elements if they don't already exist, which can lead to strings of "use of _ on uninitialized value" errors.
HTH,
--jay
