Thanks Rex:
Please help me in knowing one more related thing. I have from this script of
mine an output like this:
0.0 0.00
0.4 60.37
0.8 106.29
1.2 140.56
1.6 168.75
2.0 186.37
2.4 207.82
2.8 225.45
3.2 235.88
3.6 245.55
4.0 250.61
4.4 260.06
4.8 264.60
5.2 271.11
5.6 272.90
6.0 275.62
6.4 283.33
6.8 283.55
7.2 284.58
7.6 285.22
8.0 287.51
8.4 290.38
8.8 294.09
9.2 297.01
9.6 296.16
10.0 291.57
10.4 292.88
10.8 297.28
11.2 301.13
I want to see it formatted more beautifully, i.e. decimals under decimals.
How do we get that. My script is:
use strict;
use warnings;
my $mdout_file = "mdout.txt";
my $mdout_xtemp_file = "temp.txt";
open IN, $mdout_file or die;
open OUT, ">$mdout_xtemp_file" or die;
while (<IN>)
{
if ($_ =~ ( /TEMP/ ))
{
my $time = (substr($_, 30, 14));
$time =~ s/\s//g;
my $temp = (substr($_, 53, 10));
$temp =~ s/\s//g;
$time = sprintf("%0.1f", ($time * 2));
foreach ($time)
{
print OUT $time ;
print OUT " ";
foreach ($temp) {
print OUT $temp;
print OUT "\n";
}
}
}
}
Thanks again!
Cheers
v
From: Rex Rex <[EMAIL PROTECTED]>
To: Vineet Pande <[EMAIL PROTECTED]>
CC: beginners@perl.org
Subject: Re: converting to FLOATING_POINT..
Date: Wed, 17 Aug 2005 11:14:02 -0400
Replace,
$time = ($time * 2.0);
to
$time = sprintf("%0.2f", ($time * 2));
That should do it.
perldoc -f sprintf
-- Rex
On 8/17/05, Vineet Pande <[EMAIL PROTECTED]> wrote:
> Hi:
>
> In the following piece of script, I would like to convert the $time
after *
> by 2.0 to floating point, for instance i want 0*2 to be printed as 0.0;
How
> to do that?
>
>
> if ($_ =~ ( /TEMP/ ))
>
> {
>
> my $time = (substr($_, 30, 14));
> $time =~ s/\s//g;
> my $temp = (substr($_, 53, 10));
> $temp =~ s/\s//g;
> $time = ($time * 2.0);
> $time = ?????????????????#convert to
floatpoint
> foreach ($time)
> {
> print OUT $time ;
> print OUT " ";
> foreach ($temp) {
> print OUT $temp;
> print OUT "\n";
> }
> }
>
> }
>
>
> cheerio
> vineet
>
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