Hi Bryan Harris -
At 2005-12-03, 19:19:02 you wrote:
>
>
>I just ran into this today, and have no clue what's going on:
>
>% perl -e 'print 10-5.5, "\n"'
>4.5
>% perl -e 'print 10-05.5, "\n"'
>55
>
>How does 10 minus 5.5 equal 55? Obviously it's the leading zero, but I
>can't think of any reason why it should do that...
>
>- B
>
It seems that 05 is taken as octal (leading zero literals are octal),
and there not being an 'octal' point supported, '.' is takee as a concat. so :
decimal 10 - octal 5( which is decimal 5 also ) = 5 conat 5 => 55
Aloha => Beau;
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2005-12-03
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