The carrot is a special char, so if you want that to be included as a carrot and not a "start of string" marker, it too would have to be escaped.
To do the replace that you wanted, I'd do the following. I have a text string = "^0176 ^0176" $_=s/\^0176\ \ \^0176/\^0176\ \ /; This will substitute your exact string of ^0176<space><space>^0176 with the exact string ^0176<space><space> If you're not keeping your trailing spaces, make sure your not chomping or chopping your variable later in your script. -Mike -----Original Message----- From: Bowen, Bruce [mailto:[EMAIL PROTECTED] Sent: Monday, February 13, 2006 10:45 AM To: Michael Gargiullo Subject: RE: substitution It did but the suggestion did not work. They had me placing \ in front of the ^. I'll try this also. TX, Bruce -----Original Message----- From: Michael Gargiullo [mailto:[EMAIL PROTECTED] Sent: Monday, February 13, 2006 10:35 AM To: Bowen, Bruce Subject: RE: substitution This has probably been answered, but you need to escape your spaces ... "^0176\ \ " -Mike -----Original Message----- From: Bowen, Bruce [mailto:[EMAIL PROTECTED] Sent: Sunday, February 12, 2006 4:32 PM To: beginners@perl.org Subject: substitution I have a text string = "^0176 ^0176" I have set $a = "^0176 ^0176"; I have set $b = "^0176 "; I'm using text =~ s/$a/$b/g; And the text string doesn't change. I expected it to come out as "^0176 " after the substitution. What is wrong with my logic? Bruce Bowen 401-568-8315 -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] <http://learn.perl.org/> <http://learn.perl.org/first-response>
