[EMAIL PROTECTED] wrote: > I have a rather large group of files (~5000) that I would like to sort > into directories by date. Initially by year, then perhaps later by > year/month. > > I'm looking at the -M operator, but it seems like that would require you > find the number of days of the year, today is, then do the math. > > I'm wondering if there isn't a more efficient method.
What you probably need is something like this: my ( $mon, $year ) = ( localtime( ( stat $filename )[ 9 ] ) )[ 4, 5 ]; $mon++; $year += 1900; John -- use Perl; program fulfillment -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] <http://learn.perl.org/> <http://learn.perl.org/first-response>
