You should show us some code.
Normally you would do this in the subroutine:
sub routine {
my $mydir = shift;
# which puts the value of $_[0] into $mydir
# and then removes that from the argument list
chop $mydir;
# do stuff with $mydir
}
That makes a copy of the value. It sounds like you are doing this:
sub routine {
chop $_[0];
# do stuff with $_[0]
}
which is harder to understand, since $_[0] has no meaning for anyone,
and has the disadvantage of changing your original value.
If for some reason you sometimes need to pass the original variable
and sometimes pass a copy of the value to your subroutine, you could
pass it an expression that returns the value of $a. There's probably
a good way I can't think of to do this in all circumstances, but if
it's a string you could call it with
routine("$a");
or if it's a number,
routine($a + 0);
By the way, you should look at "chomp" and see if it's more like what
you want than "chop". Maybe it is; maybe it isn't.
On Jul 4, 2006, at 10:17 AM, [EMAIL PROTECTED] wrote:
I have a subroutine that, amongst other things, chops a scalar
variable,
$dir, passed to it as an argument. The problem is that I need $dir
intact (ie
unchopped) after calling said subroutine, but it has been altered
by the chop.
--
Aaron Priven, [EMAIL PROTECTED], http://www.priven.com/aaron
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