On 9/5/06, Michael Alipio <[EMAIL PROTECTED]> wrote:
Hi,
Suppose I have the output of this command
date +%d.%H
which outputs:
06.11
I want to adjust the last two digits to less 1:
such that it becomes 06.10..
how do I do that?
perhaps something like this.
s/\d+$/(regexp being lookup minus 1/
thanks!
s/\.(\d+)$/$1-1/e
But as Adriano pointed out, a simple subtraction won't do what you
want. 6.00 will become 6.-1.
you could get around that by doing something like:
s/\.(\d+)/$1 > 0 ? $1-1 : 0/e
But that still probably won't do what you want, because 6.00 - 1
should really be 5.23 in most cases.
Your best bet is to look at a module like Date::Manip or Date::Calc.
also, there's no reason to run `date` as an external command. See
perl's built-in localtime() function.
HTH,
-- jay
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