Derek B. Smith wrote:
--- "Dr.Ruud" <[EMAIL PROTECTED]> wrote:
Norbert Preining schreef:
The Perl Book says: Auto increment and decrement
work as in
C. So if I take this C program:
#include <stdio.h>
#include <stddef.h>
int main() {
int a;
int b;
a=3;
b=(++a)+(a++);
printf("b=%d\n",b);
}
it prints b=8.
When I do the same in perl:
$a = 3;
$b = (++$a) + ($a++);
print "b=$b\n";
It prints b=9.
I checked with a friend and Java behaves like C
and prints 8.
$ perl -wle '
$a = 3;
$b = 0 + (++$a) + ($a++);
print "b=$b\n";
'
b=8
:)
Lessons learned....
always initialize your variables to zero. : )
That's not initialising the variable, its, sort of, initialising the expression.
$b = 0;
$b += ++$a + $a++;
(the parentheses are irrelevant) also gives 9. This looks like a bug to me, and
v5.6 does it as well. Unless anyone can persuade me that this is correct
behaviour?
Rob
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