>If I have 'my $aryRef = [EMAIL PROTECTED]' can do 'push $aryRef, $aValue'? >Does this >place the value of $aValue directly into @array or do I need to figure out >another way to do that? >
You can't do 'push' like this way since $aryRef is a scalar but 'push' expect a list as its first argument. Just replace it as: push @$aryRef,$aValue; -- Books below translated by me to Chinese. Practical mod_perl: http://home.earthlink.net/~pangj/mod_perl/ Squid the Definitive Guide: http://home.earthlink.net/~pangj/squid/ -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/
