Michael Alipio schreef: > #I have this string: > > my $string = 'vd=root,status='; > > #Now, I want to transform it into: > > 'vd=root;status=' > > #That is replace the comma(,) between root and status with semicolon > (;); > > > $string =~ s/vd=\w+(,)/;/; > print $string,"\n"; > > #And it prints: > > ;status= > > Can you tell me why it has ate up vd= as well? > And how to get around with it..
Because the "vd=\w+" is part of the search-string, it will be replaced. The () around the comma don't do what you expect. You can't make the "vd=\w+" a zero-width positive look-behind assertion yet (see `perldoc perlre`) because the length of \w+ is not fixed. So you need to capture that part: $string =~ s/\b(vd=\w+),/$1;/; -- Affijn, Ruud "Gewoon is een tijger." -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/
