From: Alan <[EMAIL PROTECTED]> > It's a different case here ie not a var, instead it's a command line that's > entered into a shell, such command line being passed to Perl. And the > command needs to make it to Perl without getting altered before it gets to > Perl. > > -s "\.properties$" > > In that part of the command line, in this case the $ happens to also be a > bash > shell meta (or possibly interpreted) character. > > In this context, I was alledging that perhaps the quotes (on that command > line) tell the bash shell to keep it literal (do not interpret the special > character $). > > But, I don't know much. I guess there's even a way to run a Perl script > without going through a shell in order to run the Perl script. If so, I > don't know how to do it.
Sorry, I was not paying attention to the thread so I may be off. If you mean from within another script you may use the multiple parameter form of system(): system( $^X, $path_to_script, $param1, $param2, $param3); This way the shell is not involved in any way. Though of course it also means that you can't specify any redirection or anything like that this way. Jenda ===== [EMAIL PROTECTED] === http://Jenda.Krynicky.cz ===== When it comes to wine, women and song, wizards are allowed to get drunk and croon as much as they like. -- Terry Pratchett in Sourcery -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/
