On 4/4/07, Michael Gargiullo <[EMAIL PROTECTED]> wrote:
I have a log file I'm parsing that has special characters at the end of each row. In vi it appears to be ^@ I've already tried chomp and s/\^\@// Neither work. Does any one have any ideas?
You can match what vi(m) displays as '^@' by typing ctrl-v ctrl-shift-2 in your substitution regex. -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/
