On Fri, 2007-04-27 at 12:45 -0400, Chas Owens wrote:
> On 4/27/07, Pierre Mariani <[EMAIL PROTECTED]> wrote:
> > On Fri, 2007-04-27 at 12:03 -0400, Chas Owens wrote:
> > > On 4/27/07, Pierre Mariani <[EMAIL PROTECTED]> wrote:
> > > snip
> > > > > - modify_variable() doesn't appear to modify anything, otherwise why
> > > > > are you assigning its return value to the scalar passed as a
> > > > > parameter?
> > > > > It seems to be just a function.
> > > >
> > > > Modify_variable modifies its input variable.
> > >
> > > I think the issue is what you mean by "modifies". In order to say
> > > that the modify_variable function modifies its input then something
> > > like the following must be true:
> > >
> > > my $foo = 5
> > > modify_variable($foo)
> > > print "$foo\n"; #prints "6\n"
> > >
> >
> > Yeah, that's exactly it.
>
Sorry, I realize I replied to fast and was wrong. The way the function
works is:
my $foo = 5;
$foo = modify_variable($foo);
print "$foo\n"; #prints "6\n"
> Then why are you doing this
>
> $_ = modify_variable($_)
>
> in all of your examples?
> snip
> > Agree on that, but given other details that I didn't communicate, it is
> > not quite possible (this is actually a pl/perlu function in postgresql,
> > the variables I am working on are passed to the function, and their type
> > is limited by the function definition, so unless I create a composite
> > type I can't pass them as an array directly).
> snip
>
> Perhaps you should describe the full situation then. Without that
> information we will not be able to help you very much; we will end up
> just shooting in the dark at what we think the problem is.
Thank you, but I got it to work the way I wanted, thanks to Matthew and
Rob's posts:
map { modify_variable(${$_}) } = \($var1, $var2, $var3);
I was continuing the discussion just for the sake of it...
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