Paul Lalli schreef: > Dr.Ruud: >> Adriano Ferreira: >>> Definitely go with >>> my $test = Some::Module->new; >> >> or even with: >> my $test = Some::Module::->new(); > > For the love of $DEITY, why?
<quote src="Johan Vromans"> If you use A::B::->new(); you'll get a compile time check on whether module A::B is loaded as a bonus. </quote> <quote src="Elizabeth Mattijsen"> $ perl -wc -e 'Foo->new' -e syntax OK $ perl -wc -e 'Foo::->new' Bareword "Foo::" refers to nonexistent package at -e line 1. -e syntax OK $perl -wc -e '$Foo::a = 1; Foo::->new' Name "Foo::a" used only once: possible typo at -e line 1. -e syntax OK So the bonus is not about that the module is loaded, but about the existence of the namespace. You need to check %INC to find out whether the system thinks that the module is loaded. </quote> -- Affijn, Ruud "Gewoon is een tijger." -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/
