Unless im being very stupid in what your requirements are
If(defined $variable && $variable ne "0") {
}
-----Original Message-----
From: Jesse Farrell [mailto:[EMAIL PROTECTED]
Sent: 14 August 2007 21:18
To: beginners@perl.org
Subject: Recognizing integer as string for if statement
Is there a way to have a variable recognized as a string even if it contains
a valid integer? I have a script that is taking strings from a file that
can be numbers, including zero. I have an if statement to simply see if the
variable exists (otherwise I need to throw an error), and if the variable
contains 0, the if statement is failing. Right now, my code is essentially:
if ($variable) {
# act on $variable
} else {
# throw error
}
Is there an easy way to get the if statement to recognize a 0, or do I need
to add a special case? I don't care to keep the 0 as an integer, if I can
change it to a string somehow, that would work great.
---
Jesse Farrell
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