Hello, I'm having a problem with a regular expression in some code that I inherited.
I'm reading from a file and looking for certain parameters (mrn, enc, date, report_subtitle). The file looks like this: %%start %mrn%02333699 %fac%A %gpi% %enc%9720100004 %date%07/07/2007^14:29 %report_type%amit %report_subtitle%OCR (nut %phys_id1%GLENN %phys_id2%RAJPAL %%Pages: 5 %!PS-Adobe %%Title: (orderNotes_1) %%CreationDate: 09/11/07 14:29 %%For: System Man PRINGLE, GLENN O showpage %%PageTrailer end %%Trailer %%thisWasThePreviousStart %mrn%02333699 %enc%0720100004 %date%09/30/2007^23:59 %report_type%PCM %report_subtitle%Order Confirmation Report (nut %phys_id1%PRINGLE My problem is that the regular expression is only displaying the first item (mrn) but it won't display the others (enc, date, report_subtitle) My code is on the following line #!/usr/bin/perl #open(FILE, "3688001.ps"); open(FILE, "1234567.txt"); while ($buf = <FILE>) { #print "$buf\n"; if ($buf =~ m/\%mrn\%(\d+).+ \%enc\%(\d+).+ \%date\% (\d{1,2})\/ (\d{1,2})\/ (\d{1,2})\^.+ ^\%report_subtitle\%(.+)\( /xms) { ##################################################################### ## debug messages for matches ##################################################################### print "HERE --> 1=<$1>\n" if (defined($1)); print "HERE --> 2=<$2>\n" if (defined($2)); print "HERE --> 3=<$3>\n" if (defined($3)); print "HERE --> 4=<$4>\n" if (defined($4)); print "HERE --> 5=<$5>\n" if (defined($5)); print "HERE --> 6=<$6>\n" if (defined($6)); print "HERE --> 7=<$7>\n" if (defined($7)); } } 1; I would appreciate if anybody can tell me what I'm doing wrong or missing. Thanks, Glenn Pringle -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/