Kaushal Shriyan wrote:
Hi,
I am referring to http://www.gnulamp.com/perlscalars.html
$a = $b; # Assign $b to $a
Note that when Perl assigns a value with *$a = $b* it makes a copy of $b and
then assigns that to $a. Therefore the next time you change $b it will not
alter $a.
I did not understand the Note:- Can some one make me understand this
statement with examples
All they're saying is that $a = $b doesn't tie $a and $b together in any way,
it just copies the value of $b to $a. If you change $b after that it won't
alter $a again.
and also what i understand from the below statements( I have added in the
comments), is it correct.
$a += $b; #is it $a = $a + $b;
$a -= $b; #is it $a = $a - $b;
$a .= $b; #is it $a = $a . $b;
Exactly right. Well done.
Rob
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