Robert Citek wrote:
How can I get rid of the @foo?This does what I want, but uses the "temporary" variable @foo: $ ls | perl -e '@foo=<>; chomp @foo ; print join(" ", @foo)' This eliminates the temporary variable but doesn't work: $ ls | perl -e 'print join(" ", chomp(<>))'
$ ls | perl -l40p012e1 $ ls | tr '\n' ' ' John -- Perl isn't a toolbox, but a small machine shop where you can special-order certain sorts of tools at low cost and in short order. -- Larry Wall -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/
