ok, I found my error, it should be as follows if I want to match number 6:-
my $_ = 62; if( $_ =~ /^6$/){
----- Original Message -----
From: <[EMAIL PROTECTED]>
To: <beginners@perl.org>
Sent: Wednesday, April 02, 2008 5:07 PM
Subject: simple reg ex matching
Hi,
The value of $_ is 62. In the script below, I just wonder why the default
variable match the number 6. What I wanted to say is that if the default
variable $_ holding the value of 62, if match the number 6, then print Yes
match. So what is the right way to right.
Thanks
use strict;
use warnings;
my $_ = 62;
if( $_ =~ /6/){
print "Yes match \n";
}else{print "no"};
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