The \w character class matches any "word" character where "word" is
defined as any alphabetic character or any numerical digit or the '_'
character. The '|' which is used for alternation outside of a character
class just matches a literal '|' character inside a character class. The
\s character class matches any whitespace character.
Ok, it makes sense now that I know that the '|' is literal in the
context that I had it.
This is more about receiving feedback and not about an answer, so as I
go find out why things work as they have been described, would you
project the statement as if you had written it yourself, just for
comparison sake?
I don't think I understand your last question.
What I mean is, if you were to use a regex as opposed to using split(),
how would you have written:
if (/.*simscan~\[\d+\]~([\w|\s]+).*?~(\d+\.\d+)s~.*?~(.*?)~(.*?)~(.*)/) {
...to do the task I originally requested help with?
Steve
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