On Nov 12, 6:55 am, [EMAIL PROTECTED] (Rob Dixon) wrote:
> [EMAIL PROTECTED] wrote:
> > Hi I am new to this group and to Perl.
>
> > I am having trouble with searching and replacing a pattern in a file
> > and then
> > copying to a new file. I am trying to write an interactive program to
> > do this
> > where I input the file name for the search and replace and the file
> > name
> > for the modified file to be saved.
>
> > Here is my code.
> > Can anyone offer any suggestions?
> > Thanks in advance.
>
> > #!/usr/bin/perl -w
> > use strict;
>
> > my $input;
> > my $output;
> > my $search;
> > my $replace;
>
> > print "enter an input file name:\n";
>
> > $input = <STDIN>;
> > chomp ($input);
>
> > print "enter an output file name:\n";
>
> > $output = <STDIN>;
> > chomp ($output);
>
> > print "enter a search pattern:\n";
>
> > $search = <STDIN>;
> > chomp ($search);
>
> > print "enter a replacement string:\n";
>
> > $replace = <STDIN>;
>
> > 's/$search/$replace/g' $input >> $output;
>
> You need to open your input and output files, then lines from the input file,
> modify them, and write them to the output file one at a time.
>
> HTH,
>
> Rob
>
> #!/usr/bin/perl
> use strict;
> use warnings;
>
> print "enter an input file name:\n";
> my $input = <STDIN>;
> chomp ($input);
>
> print "enter an output file name:\n";
> my $output = <STDIN>;
> chomp ($output);
>
> print "enter a search pattern:\n";
> my $search = <STDIN>;
> chomp ($search);
>
> print "enter a replacement string:\n";
> my $replace = <STDIN>;
> chomp ($replace);
>
> open my $in, '<', $input or die "Can't open '$input': $!";
> open my $out, '>', $output or die "Can't open '$output': $!";
>
> while (<$in>) {
> s/\Q$search/$replace/g;
> print $out $_;
>
>
>
> }- Hide quoted text -
>
> - Show quoted text -- Hide quoted text -
>
> - Show quoted text -
Thanks a lot, Rob.
That works great.
I think I understand most of your suggestions but I'm not very clear
in this line:
print $out $_; # in the while loop below.
while (<$in>) {
s/\Q$search/$replace/g;
print $out $_;
What is the $_ variable?
Is that an element of the @ARGV array?
If so, is my output file saved in $_ temporarily until it is 'sent'
to
the $out file handle and then copied $output?
Please excuse my ignorance if I am totaly off.
Mark
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