On Tue, Dec 9, 2008 at 16:04, Mr. Shawn H. Corey <[EMAIL PROTECTED]> wrote: > On Tue, 2008-12-09 at 15:55 -0500, David Shere wrote: >> On Tue, 2008-12-09 at 15:51 -0500, Mr. Shawn H. Corey wrote: >> > print '', (split( /\./, $ipAddress ))[-1]; >> >> Thanks. I was searching for about an hour before I posted here; I found >> an answer online a few minutes later: >> >> http://www.perlmonks.org/?node_id=299283 >> >> Curious: What's the '', for? Scalar context? > > So print won't that the first parenthesis as part of its function. An > alternative is: > > print ((split( /\./, $ipAddress ))[-1]); > > See `perldoc -f print` for details. snip
The canonical way of telling a function that the parenthesis the follow do not belong to it is to use unary +: print +(1,2,3,4)[-1], "\n"; from http://perldoc.perl.org/perlop.html#Symbolic-Unary-Operators Unary "+" has no effect whatsoever, even on strings. It is useful syntactically for separating a function name from a parenthesized expression that would otherwise be interpreted as the complete list of function arguments. (See examples above under "Terms and List Operators (Leftward)".) -- Chas. Owens wonkden.net The most important skill a programmer can have is the ability to read. -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/
