Good question. I'm -. too smart. It should be a big black square with a 1
square border of white.
If you run this code in jqt you'll see the difference between S and -. S
load 'viewmat'
GRB=:1 0 2{"1 (#:i.8){0 255
]S=:(0=|.|:|.B)+.0=B=:<./~i.11
GRB viewmat S
GRB viewmat -.S
However, I was using JHS and got a single black line. After a carriage
return I got a big black square. Today I get:
[load 'viewmat'
GRB=:1 0 2{"1 (#:i.8){0 255
]S=:(0=B)+.0=B=:|.|:|.A=:i.11
1 0 0 0 0 0 0 0 0 0 0
GRB viewmat S
|value error: getalpha
| opaque=.*./255=, getalpha y
You don't see a white border on a white JHS screen.
Linda
-----Original Message-----
From: [email protected]
[mailto:[email protected]] On Behalf Of Raul Miller
Sent: Sunday, November 9, 2014 1:52 AM
To: Beta forum
Subject: Re: [Jbeta] GRB problem
What would "correctly" be?
Thanks,
--
Raul
On Sat, Nov 8, 2014 at 4:17 AM, Linda Alvord <[email protected]>
wrote:
> Every way I define S I get an incorrect image. Can you write an S that
> displays correctly? My result is a colid black square.
>
>
>
> load 'viewmat'
>
> GRB=:1 0 2{"1 (#:i.8){0 255
>
>
>
> A=:i.11
>
> ]S=:
>
> 1 1 1 1 1 1 1 1 1 1 1
> 1 0 0 0 0 0 0 0 0 0 1
> 1 0 0 0 0 0 0 0 0 0 1
> 1 0 0 0 0 0 0 0 0 0 1
> 1 0 0 0 0 0 0 0 0 0 1
> 1 0 0 0 0 0 0 0 0 0 1
> 1 0 0 0 0 0 0 0 0 0 1
> 1 0 0 0 0 0 0 0 0 0 1
> 1 0 0 0 0 0 0 0 0 0 1
> 1 0 0 0 0 0 0 0 0 0 1
> 1 1 1 1 1 1 1 1 1 1 1
>
>
>
> GRB viewmat S
>
>
>
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