On Tue, Jan 3, 2023 at 10:40 PM Henry Rich <[email protected]> wrote: > What is the integral of (i. 0)?
When integrating we add an arbitrary constant to represent the unknown constant which would have been lost during differentiation. By convention, J tends to use 0 to represent arbitrary constants when there's no overriding issue. So here, the integral would either be ,0 or i.0 though of course, any single element numeric list would technically be valid. > If (i. 0) as a polynomial is the same as 0, the answer has to be 0 1, > which is inconsistent with simple definitions. I think you should double check your math here. The integral of ,1 would be 0 1. Thanks, -- Raul ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
