In kbeta: (2 2 $ 0 1 2 3) p."2 1 (1 2$4 4) 228 228 (2 2 $ 0 1 2 3) p."2 1 (2$4 4) 4 14 (2 2 $ 0 1 2 3)&p."1 (1 2$4 4) 228 228 (2 2 $ 0 1 2 3)&p."1 (2$4 4) 4 14
In jbeta and earlier these all correctly returned 4 14 . Henry Rich ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
