On 4/14/08, Mark D. Niemiec <[EMAIL PROTECTED]> wrote:
> True. However, I think that in this case, _. shouldn't be
> produced at all (for much the same reason that J treats 0 = 0*_
> and 0 = 0%0, even though the hardware produces NaN in both cases.)

But 0 and _ are consistent arguments.

Mathematically speaking, _. is an inconsistent argument.

-- 
Raul
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