Commit: 2015e3984254a41d1f9f14ac854649aa132334ee
Author: Brecht Van Lommel
Date:   Mon Mar 8 13:59:16 2021 +0100
Branches: blender-v2.92-release
https://developer.blender.org/rB2015e3984254a41d1f9f14ac854649aa132334ee

Fix Cycles CUDA build error with Visual Studio 2019 v16.9

Something in this update broke the floor() function in CUDA, instead use
floorf() like we do everywhere else in the kernel code. Thanks to Ray
Molenkamp for identifying the solution.

===================================================================

M       intern/cycles/kernel/kernels/cuda/kernel_cuda_image.h

===================================================================

diff --git a/intern/cycles/kernel/kernels/cuda/kernel_cuda_image.h 
b/intern/cycles/kernel/kernels/cuda/kernel_cuda_image.h
index 82ad9225fc3..132653fa7ca 100644
--- a/intern/cycles/kernel/kernels/cuda/kernel_cuda_image.h
+++ b/intern/cycles/kernel/kernels/cuda/kernel_cuda_image.h
@@ -68,8 +68,8 @@ ccl_device T kernel_tex_image_interp_bicubic(const 
TextureInfo &info, float x, f
   x = (x * info.width) - 0.5f;
   y = (y * info.height) - 0.5f;
 
-  float px = floor(x);
-  float py = floor(y);
+  float px = floorf(x);
+  float py = floorf(y);
   float fx = x - px;
   float fy = y - py;
 
@@ -95,9 +95,9 @@ ccl_device T kernel_tex_image_interp_tricubic(const 
TextureInfo &info, float x,
   y = (y * info.height) - 0.5f;
   z = (z * info.depth) - 0.5f;
 
-  float px = floor(x);
-  float py = floor(y);
-  float pz = floor(z);
+  float px = floorf(x);
+  float py = floorf(y);
+  float pz = floorf(z);
   float fx = x - px;
   float fy = y - py;
   float fz = z - pz;
@@ -127,9 +127,9 @@ ccl_device T kernel_tex_image_interp_tricubic(const 
TextureInfo &info, float x,
 template<typename T, typename S>
 ccl_device T kernel_tex_image_interp_tricubic_nanovdb(S &s, float x, float y, 
float z)
 {
-  float px = floor(x);
-  float py = floor(y);
-  float pz = floor(z);
+  float px = floorf(x);
+  float py = floorf(y);
+  float pz = floorf(z);
   float fx = x - px;
   float fy = y - py;
   float fz = z - pz;

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