Hi! Thanks for the sugestion...
It works with this malformed path restriction.
But I get the feeling of not being perfect! :)
Regex for AS-PATH filters would be ideal!
Or maybe a bgp_path.uniq method like bgp_path.last and bgp_path.first
bgp_path.uniq could remove all repeated ASes. Then the if would be
simple.
[]'s
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Marcelo Balbinot
IP/MPLS Backbone Manager at AS53062
G G NET Telecomunicações
www.gegnet.com.br
+55 49 3561 4300
+55 49 9 9923 9347
INOC 53062*100
Em 2020-01-02 17:10, Alexander Zubkov escreveu:
Hi,
Maybe something like this will work:
bgp_path ~ [= 65001 * =] && bgp_path ~ [= * 65001 65002 * =] &&
bgp_path ~ [= * 65002 65003 * =] && bgp_path ~ [= * 65003 =]
It will though pass some malformed pathes like 65001 65999 65001 65002
65003.
On Thu, Jan 2, 2020 at 2:36 PM Marcelo Balbinot <[email protected]>
wrote:
Hello
I'm having difficulty using as-path math expressions
Look at my case.
correct as-path: 65001 65002 65003
I would like to validate if the as-path of the received prefix
conforms
to the as-path above. But, I would like to allow prepend of all ASes,
so:
65001 65001 65002 65003 is valid
65001 65002 65002 65003 is valid
65001 65002 65003 65003 is valid
65001 65001 65002 65002 65002 65003 65003 is valid
65001 65999 65002 65003 is NOT valid
The best expression I found was
if (bgp_path ~ [= 65001* 65002* 65003* =]) then
but it considers the path '65001 65999 65002 65003' to be valid
With regex that would be easier, but with bird bgpmask I couldn't
solve
it.
Any suggestion?
--
Marcelo Balbinot
IP/MPLS Backbone Manager at AS53062
G G NET Telecomunicações
www.gegnet.com.br
INOC 53062*100
