On Sat, Mar 7, 2009 at 5:16 PM, Gelf Mrogen <[email protected]> wrote:
> It seems that if you're going to curry effectful functions,
> the equivalence would be:
>
> (impure fn 'a 'b -> 'c)) == (pure fn 'a -> (impure fn 'b -> 'c))

Basically, if the application is permitted to be impure, then any step
is permitted to be impure. If the application must be pure, then all
steps must be pure.
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