On Tue, 14 Jan 2014 13:51:06 -0800, Adam Back <a...@cypherspace.org> wrote:
> I saw in the math version you had said Q'=Q+H(S) and I presumed it was a
> typo, but your code says the same thing. I presume you meant Q'=Q+H(S)*G
> and therefore that Util.SingleSHA256() multiplies by G internally?
>
> Adam
>
Thanks for reviewing this. The relevant line:
byte[] q1New = EC.PointAdd(Q1, Util.SingleSHA256(S1));
SingleSHA256 is a single application of SHA256 -- named so since 'SHA256'
functions in many Bitcoin libraries too often actually run DoubleSHA256.
32 bytes are returned.
The multiplication by 'G' that you mention is part of my EC.PointAdd...
I should probably just publish all my code as MIT and be done with it ;-)
Thanks,
Jeremy
public static byte[] PointAdd(byte[] point, byte[] scalar, bool compressed
= true)
{
var point1 = new OpenSSL.Crypto.EC.Point(EcGroup, point);
var num = OpenSSL.Core.BigNumber.FromArray(scalar);
var point2 = OpenSSL.Crypto.EC.Point.Multiply(EcGroup, num,
EcBnContext);
var result = point1.Add(point2, EcBnContext);
if (compressed)
return result.GetBytes(ConversionForm.Compressed);
else
return result.GetBytes(ConversionForm.Uncompressed);
}
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