What you probably see is the received change from your transaction. You
could try creating a transaction without change and see if there is an
onCoinsReceived event too.
Also, as always, study the logfile.
On 07/10/2017 04:51 PM, Kunal Ransing wrote:
> Hi
>
> When I send coins I got callback in broadcastComplete as well
> as onCoinsReceived.
>
> I added receive listner as below:
>
> // We want to know when we receive money.
> kit.wallet().*addCoinsReceivedEventListener*(new
> *WalletCoinsReceivedEventListener*() {
> @Override
> public void *onCoinsReceived*(Wallet w, final Transaction
> tx, Coin prevBalance, Coin newBalance) {
> Coin value = tx.getValueSentToMe(w);
>
> updateTxResult(tx, value, tx.getConfidence());
>
>
> Futures.addCallback(tx.getConfidence().getDepthFuture(6), new
> FutureCallback<TransactionConfidence>() {
> @Override
> public void onSuccess(TransactionConfidence result)
> {
> //Updated tx status to confirm when depth become
> 6 block
> updateTxResult(tx, value,result);
> }
>
> });
> }
> });
>
>
> I am sending coin using below method :
> ...............
> Address to = Address.fromBase58("send-address");
> SendRequest req = SendRequest.to(to, Coin.parseCoin("0.003"));
> req.aesKey = kit.wallet().getKeyCrypter().deriveKey("--my_key--");
> req.memo = msg;
> Wallet.SendResult result = kit.wallet().sendCoins(req);
> Transaction btcTx = result.tx;
> Futures.addCallback(result.*broadcastComplete*, new
> FutureCallback<org.bitcoinj.core.Transaction>() {
> @Override
> public void *onSuccess*(org.bitcoinj.core.Transaction resTx)
> {
> //Send message to core that Mark tx as completed
> }
>
> @Override
> public void onFailure(Throwable t) {
> LOGGER.log(Level.INFO,"PayConfig_sendCoin: Something went
> wrong !!!",t);
> }
> });
> ...........
>
> When I sent coin 0.003 BTC to my mobile wallet from my backend app, I
> receive 0.000812 BTC(i.e got call in *onCoinsReceived....for all sent of
> different coin i receive this same amount*)...also got call
> in *onSuccess* where fees for sending coin is 0.000188 BTC.
>
> Please help me to understand this ?
>
> Regards,
> Kunal
>
>
>
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