On Thu, 24 May 2001, Wilbert Berendsen wrote:
> However, when running a command through sh -c, the shell will determine if
> there is a compound command (pipeline or redir.) or not.
>
> If not, sh -c will not spawn a new process for the command, but instead
> replace itself. So:
>
> sh -c 'exec netscape'
>
> yields exactly the same result as:
>
> sh -c 'netscape'
>
> So the shell will not spoil a process if it's not necessary.
I think that is a bash feature. (On some systems /bin/sh is bash.)
But not with ash (standard /bin/sh), csh or ksh.
USER PID %CPU %MEM VSZ RSS TT STAT STARTED TIME COMMAND USER PID PPID PGID
SESS JOBC STAT TT TIME COMMAND
reed 6424 0.0 0.4 556 452 p5 I+ 10:59AM 0:00.01 links reed 6424 6423 6423
7a6600 1 I+ p5 0:00.01 links
reed 6423 0.0 0.2 444 196 p5 I+ 10:59AM 0:00.00 sh -c l reed 6423 6290 6423
7a6600 1 I+ p5 0:00.00 sh -c links
I might be misunderstanding something, then why did Scott ask about it in
the first place? (I assume he doesn't use bash as /bin/sh.)
Right now I have 13 rxvt processes started by another 13 "sh -c" processes
all started by blackbox. I think these 13 "sh -c" processes are a waste of
time and resources. (Please note that my blackbox menu entries for these
rxvt's do not have any shell pipes, redirections or any other sh
functionality.)
Jeremy C. Reed
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