[EMAIL PROTECTED] wrote:
> char c;
>
> if (c == ',' || c == ':' || c == ':')
>
> as it always passes as true. Then it folds the line in some
> specious way
> and I lose three letters. I did try going to the hex code
>
> if (c == '0x3b' || c == '0x3a' || c == '0x2c')
>
> and gcc got really annoyed with me - it always passes as false, it
> appears wrong syntax?
Well... Look closer at that line. :) It should be this:
if (c == ',' || c == ':' || c == ';')
Simply because you had two colons in there instead of one colon and one
semicolon. :)
Dave
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