Hi,
I am trying to convert grub hard drive definitions (as part of an installation
script)
There a several issues. Below is a section of the code:
----------------------------------------------------------
echo "please enter the root partition drive ie; hda, hdb, sda,sda"
read DISK
if [ $DISK = "hda" ]
then
export GRUB=hd0
elif [ $DISK = "hdb" ]
then
export GRUB=hd1
elif [ $DISK = "sda" ]
then
export X=2
if [ -f /dev/hdb ]
then
$X = $X - 1
fi
export GRUB=hd$X
else
export X=3
if [ -f /dev/hdb ]
then
$X = $X - 1
fi
export GRUB=hd$X
fi
echo $GRUB
echo "please enter the partition number without the prefix ie; instead of hdb4,
just type 4"
read PARTITION
$PARTITION = $PARTITION - 1 #line 130
export NODE = "$GRUB,$PARTITION" #line 131
echo $NODE
----------------------------------------
when executed I recieve this output:
--------------------------------------------------------
please enter the root partition drive ie; hda, hdb, sda,sda
sda
hd2
please enter the partition number without the prefix ie; instead of hdb4, just
type 4
3
./INSTALLATION: line 130: 3: command not found
./INSTALLATION: line 131: export: `=': not a valid identifier
./INSTALLATION: line 131: export: `hd2,3': not a valid identifier
--------------------------------------------------------------------
ERROR 1 - I suspect this has something to do with 'read' capturing the input
value as a string rather than a number. I tried 'read' with the 'n' option but
no avail.
ERROR 2 & 3 - I suspect this has something to do with the Unix quoting
mechanisms. I tried nearly all combinations but still no cigar.
Any advice on how to solve these issues is appreciated.
Also if anyone knows a good reference on Arithmetic in Shell script please
speak up. I am using 'Linux Programming 3rd Edition' Mathews and Stones (which
is one thick book!) and there seems to be but a paragraph on aritmetic in bash.
Thanks in advance
Kevin Annies
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