On Sat, 7 May 2011 19:39:22 +0300
Jonathan Morton <[email protected]> wrote:
>
> On 7 May, 2011, at 1:10 am, Stephen Hemminger wrote:
>
> > Rate <= (MSS/RTT)*(1 / sqrt{p})
> >
> > where:
> > Rate: is the TCP transfer rate or throughputd
> > MSS: is the maximum segment size (fixed for each Internet path, typically
> > 1460 bytes)
> > RTT: is the round trip time (as measured by TCP)
> > p: is the packet loss rate.
>
> So if the loss rate is 1.0 (100%), the throughput is MSS/RTT. If the loss
> rate is 0, the throughput goes to infinity. That doesn't seem right to me.
If loss rate is 0 there is no upper bound on TCP due to loss.
There are other limits on TCP throughput like window size but not limits
because of loss.
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